药学学报
藥學學報
약학학보
ACTA PHARMACEUTICA SINICA
2002年
8期
644-648
,共5页
喷昔洛韦%阿昔洛韦%鸟嘌呤%加速试验%热稳定性%热重法%非等温动力学
噴昔洛韋%阿昔洛韋%鳥嘌呤%加速試驗%熱穩定性%熱重法%非等溫動力學
분석락위%아석락위%조표령%가속시험%열은정성%열중법%비등온동역학
aciclovir%penciclovir%guanine%accelerating test%thermal stability%thermogravimetry%non-isothermal kinetics
目的研究嘌呤类药物的热解过程及非等温动力学.方法用红外光谱技术、加速稳定性试验方法和热重仪分析方法测定分解过程,用Ozawa法以及Coast-Redfern法和MKN法处理数据确定热分解函数.结果确定了阿昔洛韦(aciclovir,Acv)、喷昔洛韦(penciclovir,Pcv)热解过程和中间产物,得到热解动力学参数活化能Ea、指前因子A.结论加速稳定性试验与热重法的计算结果一致,喷昔洛韦的热稳定性大于阿昔洛韦;两者热解第一步具有相同的中间产物鸟嘌呤,且动力学方程相同:dα/dt=Ae-Ea/RT2(1-α)3/2,均为1.5级反应过程.
目的研究嘌呤類藥物的熱解過程及非等溫動力學.方法用紅外光譜技術、加速穩定性試驗方法和熱重儀分析方法測定分解過程,用Ozawa法以及Coast-Redfern法和MKN法處理數據確定熱分解函數.結果確定瞭阿昔洛韋(aciclovir,Acv)、噴昔洛韋(penciclovir,Pcv)熱解過程和中間產物,得到熱解動力學參數活化能Ea、指前因子A.結論加速穩定性試驗與熱重法的計算結果一緻,噴昔洛韋的熱穩定性大于阿昔洛韋;兩者熱解第一步具有相同的中間產物鳥嘌呤,且動力學方程相同:dα/dt=Ae-Ea/RT2(1-α)3/2,均為1.5級反應過程.
목적연구표령류약물적열해과정급비등온동역학.방법용홍외광보기술、가속은정성시험방법화열중의분석방법측정분해과정,용Ozawa법이급Coast-Redfern법화MKN법처리수거학정열분해함수.결과학정료아석락위(aciclovir,Acv)、분석락위(penciclovir,Pcv)열해과정화중간산물,득도열해동역학삼수활화능Ea、지전인자A.결론가속은정성시험여열중법적계산결과일치,분석락위적열은정성대우아석락위;량자열해제일보구유상동적중간산물조표령,차동역학방정상동:dα/dt=Ae-Ea/RT2(1-α)3/2,균위1.5급반응과정.
AIM To study the thermal stability, decomposition process and kinetics of such purine pharmaceuticals as aciclovir (Acv), penciclovir (Pcv), and their parent substance, guanine. METHODS Using infrared technique, accelerating test method and thermogravimetry to investigate the thermal decomposition processes and using Coast-Redfern method, MKN method and Ozawa method to deal with the data to get kinetic functions. RESULTS The decomposition process and the formed products were derived, the kinetic model function was suggested by comparison of the kinetic parameters. CONCLUSION Pcv and Acv's degrading product for the first step is guanine. The sequences of their thermal stabilities is: Pcv>Acv. The two drugs' kinetic equation of thermal decomposition is expressed as: dα/dt=Ae-Ea/RT2(1-α)3/2.