CAJ | 학술논문

标题化合物C19H23NO4由苯甲醛、尿素、乙酰乙酸乙酯在微波辐射下干反应而得。结构通过单晶X-射线衍射法测定,其晶体属单斜晶系,空间群P21/c,a=9.745(2),b=7.388(2),c=24.354(5)Å,β=92.60(3)°,V=1751.6(6)Å3,Z=4,Mr=329.38,Dc=1.249g/cm3,μ(MoKα)=0.087mm-1,F(000)=704。晶体结构用直接法解出，经全矩阵最小二乘法对原子参数进行修正，最终的偏离因子为R=0.0416,wR=0.1175。在晶体结构中，二氢吡啶环与苯环之间的二面角为92.14°。
표제화합물C19H23NO4유분갑철、뇨소、을선을산을지재미파복사하간반응이득。결구통과단정X-사선연사법측정,기정체속단사정계,공간군P21/c,a=9.745(2),b=7.388(2),c=24.354(5)Å,β=92.60(3)°,V=1751.6(6)Å3,Z=4,Mr=329.38,Dc=1.249g/cm3,μ(MoKα)=0.087mm-1,F(000)=704。정체결구용직접법해출，경전구진최소이승법대원자삼수진행수정，최종적편리인자위R=0.0416,wR=0.1175。재정체결구중，이경필정배여분배지간적이면각위92.14°。
The title compound (C19H23NO4) has been synthesized by thereaction of benzaldehyde, ethyl acetoa～cetate and urea under microwave irradiation without solvent and its structure was determined by single crystal～ X-ray diffraction. The crystal is monoclinic, space group P21/c with a=9.745(2), b=7.388(2), c = 24.394(5) Å, β=92.60(3)°, V = 1751.6(6) Å3, Z = 4, Mr = 329.38, Dc = 1.249 Mg/m3, μ(MoKα)=0.087cm-1, F(000)=704. The structure was solved by direct methods and refined by full-matrix least squares method to the final R=0.0416, wR=0.1175, X-ray analysis reveals that the dihedral～ angle between plane 1(C(11)～C(15),N) and plane 2(C(21)～C(26)) is 92.14°.