CAJ | 학술논문

通过Materials Studio软件在建立完整的12CaO?7Al 2 O 3晶体结构模型的基础上逐渐减少Ca原子数，使其形成Ca空位，对钙空位量为0~1.00的12CaO?7Al 2 O 3晶体结构进行几何优化模拟，计算其晶格参量、晶体自由能、化学键布居数及键长等。结果表明：Ca空位对12CaO?7Al 2 O 3晶体结构的稳定性有显著影响，随着Ca空位量的增加，12CaO?7Al 2 O 3晶体晶格参量和晶胞体积逐渐降低，自由能逐渐增加，O—Ca键稳定性变差；当Ca空位量增加到0.75和1.00时，O—Ca键种类由4种减少到3种，且键长增大，从而导致12CaO?7Al 2 O 3晶体的稳定性逐渐降低；分别合成钙空位量为0、0.50和1.00的12CaO?7Al2O3晶体，其在碳酸钠溶液中的分解率随着钙空位量的增加而增加，晶体稳定性与晶体学模拟结果相吻合。
통과Materials Studio연건재건립완정적12CaO?7Al 2 O 3정체결구모형적기출상축점감소Ca원자수，사기형성Ca공위，대개공위량위0~1.00적12CaO?7Al 2 O 3정체결구진행궤하우화모의，계산기정격삼량、정체자유능、화학건포거수급건장등。결과표명：Ca공위대12CaO?7Al 2 O 3정체결구적은정성유현저영향，수착Ca공위량적증가，12CaO?7Al 2 O 3정체정격삼량화정포체적축점강저，자유능축점증가，O—Ca건은정성변차；당Ca공위량증가도0.75화1.00시，O—Ca건충류유4충감소도3충，차건장증대，종이도치12CaO?7Al 2 O 3정체적은정성축점강저；분별합성개공위량위0、0.50화1.00적12CaO?7Al2O3정체，기재탄산납용액중적분해솔수착개공위량적증가이증가，정체은정성여정체학모의결과상문합。
The geometry optimization simulation of 12CaO?7Al2O3 crystal with different calcium atom vacancies from 0 to 1 was performed by gradually decreasing calcium atoms based on the establishment of complete crystal structure with Materials Studio software, the corresponding lattice parameters, free energy, chemical bond population bond length were also calculated. The results show that the calcium atom vacancy has a significant effect on the stability of 12CaO?7Al 2 O 3 crystal structure. The lattice parameter and the cell volume decrease while the free energy increases with the increase of calcium atom vacancy in 12CaO?7Al 2 O 3 . The main bonds of 12CaO?7Al 2 O 3 of are O—Ca, and the number of O—Ca decreases from 4 to 3, and bond length increase when the calcium vacancy increases to 0.75 and 1.00, resulting in the stability decrease of 12CaO?7Al2O3. The 12CaO?7Al2O3 crystals with calcium atom vacancies of 0, 0.50 and 1.00 were synthesized respectively, and the decomposition rate of 12CaO?7Al2O3 in sodium carbonate solution increases as the calcium vacancy increases, the crystal stability of which is in accordance with the computer simulation results.