丢番图方程x3±27=14y2的整数解
주번도방정x3±27=14y2적정수해
On Solution of the Diophantine Equationx3±27=14y2
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    唐山师范学院学报 당산사범학원학보
    Journal of Tangshan Teachers College
    2015年 5期 9-12 ,共4页

    李润琪

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    正整数解%平凡解%丢番图方程%同余 正整數解%平凡解%丟番圖方程%同餘
    정정수해%평범해%주번도방정%동여
    positive integer solution%trivial solution%Diophantine equation%congruence
    利用奇偶数的性质、同余的性质等证明了丢番图方程23x±27=14y仅有平凡解。
    이용기우수적성질、동여적성질등증명료주번도방정23x±27=14y부유평범해。
    With the help of the natures of odd number and even number, congruence, the Diophantine equation23x±27=14y was proved to only have trivial solution.
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