差分方程x(n+1)=(δx(n-k)+x(n-k-1))/(A+x(n-k-1))全局性质
차분방정x(n+1)=(δx(n-k)+x(n-k-1))/(A+x(n-k-1))전국성질
Global behavior of the difference equation x(n+1)=(δx(n-k)+x(n-k-1))/(A+x(n-k-1))
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